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4x^2-5x=136/3
We move all terms to the left:
4x^2-5x-(136/3)=0
We add all the numbers together, and all the variables
4x^2-5x-(+136/3)=0
We get rid of parentheses
4x^2-5x-136/3=0
We multiply all the terms by the denominator
4x^2*3-5x*3-136=0
Wy multiply elements
12x^2-15x-136=0
a = 12; b = -15; c = -136;
Δ = b2-4ac
Δ = -152-4·12·(-136)
Δ = 6753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{6753}}{2*12}=\frac{15-\sqrt{6753}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{6753}}{2*12}=\frac{15+\sqrt{6753}}{24} $
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